1. Find an expression for a side length of the square.
For this case, the first thing to do is to know that the area of a square is:
A = L ^ 2
Where
L: side of the square.
We then have to factorize the given polynomial:
z ^ 2 + 12z + 36
(z + 6) * (z + 6)
Rewriting:
z ^ 2 + 12z + 36 = (z + 6) ^ 2
Answer:
The side of the square is:
L = (z + 6)
2. Find the perimeter when z = 12.
The perimeter of a square by definition is:
P = 4L
Where
L: side of the square.
Substituting we have:
P = 4 (z + 6)
For z = 12 we have:
P = 4 (12 + 6)
P = 72
Answer:
the perimeter when z = 12 is:
P = 72
If helpful, please mark as brainliest! =)
