Answer:
155.5%
Explanation:
from the equation
2mol of Na3PO4 reacts to give 6mol of Nacl
therefore 6.12mol of Na3PO4 will give 18.36mol of Nacl
2mol Na3PO4............ 6mol of nacl
6.12mol NaPO4.......... 6×6.12mol/2mol = 18.36mol of Nacl
mass of Nacl = mol × molar mass
where molar mass of Nacl= 23+12=35g/mol
mass of Nacl= 18.36 × 35= 642.6g of Nacl
percentage yield = actual yield/ theoretical yield ×100%
percentage yield= 1001g (given)/642.6g(used) ×100 = 155.5%
