I have this question on a homework and don't know how to do It
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Area of a triangle = 1/2 x length x height.
80 = 1/2 x (x+1) (2x-2)
Multiply both sides by 2:
160 = (x+1)(2x-2)
Expand the right side:
160 = 2x^2 -2
Add 2 to both sides:
162 = 2x^2
Divide both sides by 2:
81 = x^2
Take the square root of both sides:
x = 9
Now find the length of the s1des:
(x+1) = 9+1 = 10
2x-2 = 2(9) -2 = 18-2 =16
The shorter side is 10