Respuesta :
Answer:
This is not possible
W = width of cardboard to start with
W+6 = length of cardboard to start with
H =2 (height of finished box)
volume = W x L x H = 14 in^3
if H=2 in, then the area of the base before cutting out the 2x2 corners is W x L = 7 in^2
This is not enough area to cut out the 4 corners of 2x2 each, which would be 16 in^2
W=width
L=Length
Two equations
1) W+6=L
2) (W-4)*(L-4)*2=14
Solve
(W-4)*(W+6-4)*2=14
(W-4)*(W+2)*2=14
(W-4)*(W+2)=7
W^2-2W-8=7
W^2-2W-15=0
Factor
(W-5)*(W+3)=0
W-5=0
W=5
L=W+6
L=5+6
L.=11
Answer
W=5
L=11
L=Length
Two equations
1) W+6=L
2) (W-4)*(L-4)*2=14
Solve
(W-4)*(W+6-4)*2=14
(W-4)*(W+2)*2=14
(W-4)*(W+2)=7
W^2-2W-8=7
W^2-2W-15=0
Factor
(W-5)*(W+3)=0
W-5=0
W=5
L=W+6
L=5+6
L.=11
Answer
W=5
L=11