Answer:
[tex] \huge \boxed{ \boxed{ \sf \: \frac{1}{2} }}[/tex]
Step-by-step explanation:
to understand this
you need to know about:
given:
- area:[tex]\frac{9}{20}[/tex]
- length:[tex]\frac{9}{10}[/tex]
to find:
tips and formulas:
let's solve:
let width be w
according to the question
the equation is
[tex] \sf \frac{9}{10 } \times w = \frac{9}{20} [/tex]
let's figure out the equation
- [tex] \tt \: divide \: both \: sides \: by \: \frac{9}{10} : \\ \sf\frac{9}{10} \div \frac{9}{10} \times w = \frac{9}{20} \div \frac{9}{10} [/tex]
- [tex] \tt simplify : \\ \sf\frac{9}{10} \times \frac{10}{9} \times w = \frac{9}{10} \times \frac{10}{9} \\ \therefore \: \tt \: w = \frac{1}{2} [/tex]