PLS HELP ME ILL GIVE BRAINLIEST, AND PLS EXPLAIN YOUR ANSWER<3

A field has an area of 9/20 square mile. Determine the width of the field if the length is 9/10 mile long.

Respuesta :

Answer:

[tex] \huge \boxed{ \boxed{ \sf \: \frac{1}{2} }}[/tex]

Step-by-step explanation:

to understand this

you need to know about:

  • fraction
  • PEMDAS
  • equation

given:

  • area:[tex]\frac{9}{20}[/tex]
  • length:[tex]\frac{9}{10}[/tex]

to find:

  • width

tips and formulas:

  • area of a rectangle=l×w

let's solve:

let width be w

according to the question

the equation is

[tex] \sf \frac{9}{10 } \times w = \frac{9}{20} [/tex]

let's figure out the equation

  1. [tex] \tt \: divide \: both \: sides \: by \: \frac{9}{10} : \\ \sf\frac{9}{10} \div \frac{9}{10} \times w = \frac{9}{20} \div \frac{9}{10} [/tex]
  2. [tex] \tt simplify : \\ \sf\frac{9}{10} \times \frac{10}{9} \times w = \frac{9}{10} \times \frac{10}{9} \\ \therefore \: \tt \: w = \frac{1}{2} [/tex]

ACCESS MORE