Answer:
Cu(OH)₂ ⇒ copper(II) hydroxide
Explanation:
Copper(II) nitrate (Cu(NO₃)₂) dissociates into ions in an aqueous solution to form Cu²⁺ ions and NO₃⁻ (nitrate) ions. If the aqueous solution contains sodium hydroxide (NaOH), which dissociates into Na⁺ and OH⁻ ions, a precipitate is formed from Cu²⁺ and OH⁻ ions. The precipitation reaction is the following:
Cu(NO₃)₂(aq) + 2 NaOH(aq) → Cu(OH)₂(s) + 2 NaNO₃(aq)
The light blue precipitated formed is copper (II) hydroxide (Cu(OH)₂), because it is an insoluble solid product.
