Answer:
Please find attached the required triangle drawn with Microsoft Visio
Step-by-step explanation:
The isosceles triangle ΔPQR we are to construct has the following parameters;
∠PQR = 90°
Length of side hypotenuse PR = 4 cm
Therefore, given that the triangle is right triangle is an isosceles triangle the length of each of the side legs are equal
Therefore, we have;
Length of PQ = Length of QR
The length of the legs , [tex]\overline {PQ}[/tex] and [tex]\overline {QR}[/tex], are given by Pythagoras's theorem as follows;
[tex]\overline {PR}[/tex] = √([tex]\overline {PQ}[/tex]² + [tex]\overline {QR}[/tex]²) = √([tex]\overline {PQ}[/tex]² + [tex]\overline {PQ}[/tex]²) = [tex]\overline {PQ}[/tex]·√2
∴ [tex]\overline {PQ}[/tex] = 4 cm/(√2) = 2·√2 cm = [tex]\overline {QR}[/tex]
The required triangle drawn with Microsoft Visio is attached