Respuesta :

Answer:

Please find attached the required triangle drawn with Microsoft Visio

Step-by-step explanation:

The isosceles triangle ΔPQR we are to construct has the following parameters;

∠PQR = 90°

Length of side hypotenuse PR = 4 cm

Therefore, given that the triangle is right triangle is an isosceles triangle the length of each of the side legs are equal

Therefore, we have;

Length of PQ = Length of QR

The length of the legs , [tex]\overline {PQ}[/tex] and [tex]\overline {QR}[/tex], are given by Pythagoras's theorem as follows;

[tex]\overline {PR}[/tex] = √([tex]\overline {PQ}[/tex]² + [tex]\overline {QR}[/tex]²) = √([tex]\overline {PQ}[/tex]² + [tex]\overline {PQ}[/tex]²) = [tex]\overline {PQ}[/tex]·√2

∴ [tex]\overline {PQ}[/tex] = 4 cm/(√2) = 2·√2 cm = [tex]\overline {QR}[/tex]

The required triangle drawn with Microsoft Visio is attached

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