Question

When you mix two substances, the heat gained by one substance is equal to the heat lost by the other substance. Suppose you place 125 g of aluminum in a calorimeter with 1,000 g of water. The water changes temperature by 2 °C and the aluminum changes temperature by –74.95 °C. Water has a known specific heat capacity of 4.184 J/g °C. Use the specific heat equation to find out how much heat energy the water gained (q). Assume that the heat energy gained by the water is equal to the heat energy lost by the aluminum. Use the specific heat equation to solve for the specific heat of aluminum. (Hint: Because heat energy is lost, the value of q is negative.)

Answer 1

From the calculation, the specific heat capacity of the aluminum is 9.5 * 10^-5  J/g °C

What is specific heat capacity?

The specific heat capacity refers to the heat that is required to raise the temperature of a body by 1K. The heat gained by the water is equal to the heat energy lost by the aluminum hence the negative sign.

Thus;

-(125 * c *  –74.95) = 1,000 g *  4.184 *  2

c =  1,000 g *  4.184 *  2/125 * 74.95

c = 8368/9368.75

c= 9.5 * 10^-5  J/g °C

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