Question

let f(x)=x^2 +2 and g(x)=1-3x. find each function value: (fg)(-1)

Answer 1

Answer:

12

Step-by-step explanation:

so basically

(x^2+2)*(1-3x)=-3x^3+x^2-6x+2

now plug in -1

-3(-1)^3+(-1)^2-6(-1)+2=12

hope this helped :)

Answer 2

The correct value of (fg)(-1) is "12". A further solution of the given query is provided below.

Given functions are:

$f(x) = x^2+2$

$g(x) = 1-3x$

Now,

⇒ $(fg) = (x^2+2)(1-3x)$

By applying multiplication, we get

           $=x^2+2-3x^3-6x$

           $=-3x^3+x^2-6x+2$...(equation 1)

By substituting the value "-1" in place of "x" in equation 1, we get

⇒ $(fg)(-1) = -3(-1)^3+(-1)^2-(6)(-1)+2$

                  $=-3(-1)+1+6+2$

                  $=3+1+6+2$

                  $=12$

Thus the right answer is (fg)(-1) = 12.

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