if n is a negative number and p is a positive number, which of the following have the lowest value?
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Answer:
A
Step-by-step explanation:
Im not sure if this is right, but I think that is the answer
If we solve each of the expression then (n-p) will have the lowest value.
Expression is like an equation and it is not only in the equal to type but only without equal to type. (n-p), np are the expressions.
We have the following expression and we have to first solve if n is a negative number and p is a positive number.
Let n=-1 and p=2
So, n-p=-1-2=-3
[tex]n^{2} p[/tex]=2
[tex](np)^{2}[/tex]=4
p-2n=0
[tex](n-p)^{2}[/tex]=9
Hence the lowest value is of n-p which is -3.
Learn more about expressions at https://brainly.com/question/723406
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