Answer:
[tex]\dfrac{1}{64}[/tex]
Step-by-step explanation:
[tex](-32)^{-1.2} = \dfrac{1}{(-32)^{\frac{6}{5}}} = \dfrac{1}{(\sqrt[5]{-32})^6}} = \dfrac{1}{(-2)^{6}} = \dfrac{1}{64}[/tex]