Given: AB=AC m∠1=m∠2 AC=15, DC=5 Find: BD, AB
![Given ABAC m1m2 AC15 DC5 Find BD AB class=](https://us-static.z-dn.net/files/d77/9e8712cb075e270ff1cab5b028b242bf.png)
Answer:
AB = 15
BD = 5
Step-by-step explanation:
Statement__________________| Reason______________
1) m<1 = m<2, AB = AC | Given
2) AD = AD | Reflexive property
3) ΔABD = ΔADC | Side - angle - side
4) AB = AC = 15 | Corresponding part of congruent triangles . | are congruent
5) BD = DC = 5 | Corresponding parts of congruent triangles . | are congruent
Answer:
Step-by-step explanation:
AB = AC and AC = 15 (both given)
AB≅AC, ∠1≅∠2, AD≅AD (first two given and the last one is the common side)
BD≅DC as corresponding sides
BD = DC and DC = 15