Answer:
Isosceles Triangle
Step-by-step explanation:
Triangle ABC has vertices A(-5, -1), B(5, -1), and C(0, -4). Is it scalene, isosceles or equilateral?
We solve this question using vertices formula:
√(x2 - x1)² + (y2 - y1)² when given vertices: (x1, y1) and (x2 , y2)
For Side AB
A(-5, -1), B(5, -1)
AB = √(5 - (-5))² + (-1 -(-1))²
AB= √(5 + 5)² + (-1 + 1)²
AB = √10² + 0
AB = √100
AB = 10 units
For Side BC
B(5, -1), C(0, -4)
BC = √(0 - 5)² + (-4 -(-1))²
BC = √-5² + (-4 + 1)²
BC = √25 + -3²
BC = √25 + 9
BC = √34
For Side AC
A(-5, -1), C(0, -4).
AC = √(0 - (-5))² + (-4 - (- 1)²
AC = √5² + -3²
AC = √25 + 9
AC = √34
Therefore this triangle is an isosceles triangle because 2 of its sides (AC and BC ) are equal to one another
