Question

An arithmetic sequence has second term 28 and the fifth term 52. (3 marks) a. Find u1 and d. b. Find u10

Answer 1

Answer: See explanation

Step-by-step explanation:

Second term = a + d = 28 ....... i

Fifth term = a + 4d = 52 ......... ii

Subtract equation I from ii

3d = 24

d = 24/3 = 8

d = common difference = 8

Since a + d = 28

a + 8 = 28

a = 28 - 8 = 20

First term = a = 20

u10 = a + (n-1)d

= a + (10-1)8

= 20 + (9 × 8)

= 20 + 72

= 92