Question

a car takes off from rest and covers a distance of 80m on a straight road in 10s. Calculate the magnitude of its acceleration​

Answer 1

Answer:

The magnitude of the acceleration is 1.6 m/s².

Explanation:

We can find the magnitude of the acceleration by using the following equation:

$x_{f} = x_{0} + v_{0}t + \frac{1}{2}at^{2}$

Where:

$x_{f}$: is the final position = 80 m

$x_{0$: is the initial position = 0

$v_{0}$: is the initial speed = 0 (it starts from rest)

a: is the acceleration =?

t: is the time = 10 s

Hence, the acceleration is:

$a = \frac{2x_{f}}{t^{2}} = \frac{2*80 m}{(10 s)^{2}} = 1.6 m/s^{2}$

Therefore, the magnitude of the acceleration is 1.6 m/s².

I hope it helps you!