Question

There are two right angle triangles, triangle ABC and Triangle EDF. Measure of angle ACB and angle EFD are 90. Side AB is congruent to side ED, Side AC is congruent to side DF. What theorem can be used to show that ABC ≅ DEF?

Answer 1

Answer:

SAS theorem

Step-by-step explanation:

Given

Triangles ABC and DEF

$AB = ED$

$AC = DF$

$\angle ACB = \angle EFD = 90^{\circ}$

Required

Which theorem shows the similarity between both triangles

The following can be deduced from the given parameters.

$AB = ED$ ===> Equal Sides

$AC = DF$ ===> Equal Sides

$\angle ACB = \angle EFD = 90^{\circ}$ ===> Equal Angle

This implies that two sides and 1 angle of both triangles are equal.

Hence, the theorem to use is the SAS theorem.