Question

Find the equation of a line perpendicular to -3x + 5y = -1 that contains the point (0, -5)

Answer 1

Answer:

y = -5/3x - 5

Step-by-step explanation:

convert -3x + 5y = -1 to slope-intercept form:

5y = 3x - 1

y = 3/5x - 1/5

slope of a line perpendicular to the above equation would be -5/3

y = mx + b

-5 = -5/3(0) + b

b = -5

y = -5/3x - 5