Answer (assuming the question allows it to be written in slope-intercept form):
[tex]y = -\frac{3}{5} x-\frac{9}{5}[/tex]
Step-by-step explanation:
1) First, find the slope of the equation. Use the slope formula [tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex], substitute the given points' x and y values, and simplify:
[tex]m = \frac{(-3)-(0)}{(2)-(-3)} \\m =\frac{-3-0}{2+3}\\m = -\frac{3}{5}[/tex]
Thus, the slope is [tex]-\frac{3}{5}[/tex].
2) Now, use the point-slope formula [tex]y-y_1 = m (x-x_1)[/tex] and substitute real values for [tex]m[/tex], [tex]x_1[/tex], and [tex]y_1[/tex].
Since [tex]m[/tex] represents the slope, substitute [tex]-\frac{3}{5}[/tex] in its place. Since [tex]x_1[/tex] and [tex]y_1[/tex] represent the x and y values of a point the line crosses, use the x and y values of any one of the given points to substitute into the formula. (Either one is fine. I chose (2,-3).) Then, isolate y to put it into slope-intercept form and find the answer:
[tex]y-(-3) = -\frac{3}{5} (x-(2))\\y + 3 = -\frac{3}{5} x + \frac{6}{5} \\y = -\frac{3}{5} x - \frac{9}{5}[/tex]
