Answer: 182.87 grams of hydrogen are necessary to react completely with 853.42g of nitrogen.
Explanation:
The balanced chemical reaction is :
[tex]N_2+3H_2\rightarrow 2NH_3[/tex]
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
[tex]\text{Number of moles of nitrogen}=\frac{853.42g}{28g/mol}=30.479moles[/tex]
According to stoichiometry:
1 mole of [tex]N_2[/tex] react with = 3 moles of [tex]H_2[/tex]
30.479 moles of [tex]N_2[/tex] will react with=[tex]\frac{3}{1}\times 30.479=91.437moles[/tex] of [tex]H_2[/tex]
Mass of [tex]H_2[/tex] =[tex]moles\times {\text {Molar mass}}=91.437mol\times 2g/mol=182.87g[/tex]
Thus 182.87 grams of hydrogen are necessary to react completely with 853.42g of nitrogen.
