Respuesta :
Considering a well-trained 130-pound female marathon runner named Jordan.
The grams of glycogen Jordan is storing in her body is 884 grams.
Given that:
- weight of the female marathon runner = 130 pounds
- mass of the glycogen = 6.8 grams / pound
a.
The total mass of glycogen that Jordan is storing in the body of 130 pounds is:
- = 130 pounds × 6.8 grams/pound
- = 884 grams
b. The amount of Calories she has stored in the body of 130 pounds is calculated as follows.
Since 1 gram is equivalent to 7.716179 kcal
∴
- 884 grams will be = (884 grams × 7.716179 kcal)/ 1 gram
- = 6821.102 kcal.
c.
Fat is a class of food that the when consumed provides energy to the body. It is usually stored as fatty acid and is measured in pounds.
One pound of fat usually requires an energy of about 3500 calories to burn.
- Since 1 pound of fat requires 3500 calories;
The weight of the glycogen in fat will be:
- = (6821.102 kcal × 1 pound of fat)/3500 kcal
- = 1.949 pounds of fat
d.
The body stores most of its extra energy as fat rather than glycogen because the body after 8 hours of eating, body starvation starts to occur. At this stage, the stored fat is designated to supply energy to the body.
e.
Given that:
- Jordan will be competing in a marathon of = 26.2 miles
- From her condition, she has enough glycogen to last for 24 miles.
In order for her to be able to run at the same pace beyond the 24 miles, she needs to consume fatty food substances that can help her store additional fat that can be used to provide energy during the marathon race.
Therefore, we can conclude that we have understood the grams of glycogen that Jordan can store in her body, the conversion from grams to calories, and how Jordan can achieve the marathon of 26.2 miles.
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