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13 g —> 0.013 kg
KE = 1/2(m)(v)^2
KE = 1/2(0.013)(8.5)^2
KE = 0.47 J
13 g —> 0.013 kg
KE = 1/2(m)(v)^2
KE = 1/2(0.013)(8.5)^2
KE = 0.47 J
The kinetic energy is 0.469 Joule.
The Kinetic energy is given as,
[tex]K.E=\frac{1}{2} m*v^{2} [/tex]
Where m is mass and v is speed of object.
Given that, [tex]m=13g=\frac{13}{1000}=0.013Kg [/tex] and [tex]v=8.5m/s[/tex]
Substitute values in above expression.
[tex]K.E=\frac{1}{2}*0.013*(8.5)^{2}=0.469Joule [/tex]
Hence, The kinetic energy is 0.469 Joule.
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