NEEDED ASAP WILL MARK AS BRAINLIEST
Here are two right-angled triangles.
Given that tan a = tan b
find the value of x.
You must show all your working.

NEEDED ASAP WILL MARK AS BRAINLIEST Here are two rightangled triangles Given that tan a tan b find the value of x You must show all your working class=

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Explanation:

This might not be how you are supposed to do it but,

We can see the two triangles are similar because AA similarity.

We know that the sides are proportional so we can make:

[tex]\frac{x+2}{x}=\frac{4}{3x-1}[/tex]

We get,

[tex]3x^2+5x-2=4x\\3x^2+x-2\\(3x-2)(x+1)=0\\x=2/3, x=-1[/tex]

Because sides can't be negative, x = 2/3

Answer:

x=2/3 = 0.7

Step-by-step explanation:

X+2/x = 4/3x-1

=(X+2)(3x-1)=4x

(x+2)(3x-1)-4x=0

3x²-x+6x-2-4x=0

3x²+x-2=0

3x²+3x-2x-2=0

3x(x+1)-2(x+1)

(x+1)(3x-2)=0

x+1=0

3x-2=0

x=-1 or 2/3

x=2/3 = 0.7

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