Answer:
Proof:
|----------(R1)-------------(R2)---------|
Let the resistances be R1 , R2 connected in series. And the potential difference be V ;
We know that :
P1 = V²/R1 ..........(1) and
P2 = V²/R2 ...........(2)
In series combination , the net resistance is the algebraic addition of individual resistance :
R = R1 + R2
=> V²/P = V²/P1 + V²/P2
=> 1/P = 1/P1 + 1/P2
Explanation:
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