Question

The compound interest on 1800 at 10% per annum, for a certain period of time is 7378. Find the
time in years.​

Answer 1

Answer:

14.8013 years

Explanation:

the equation to find this is 1800 x 1.1 ^ (n) = 7378

n is the numbers of years

1800 x 1.1 ^ (n) = 7378

1.1 ^(n) = 7378 ÷ 1800

1.1 ^(n) = 4.0989

$n = \frac{ln(4.0989)}{ln(1.1}$

$n = 14.8013$

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