Question

Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for point Q that is located two-thirds the distance from point P to point R.

4.9
4.7
2.5
2.3

Answer 1

Answer:

The answer is 4.7

Step-by-step explanation:

$y = \frac{l1y1 + l2y2}{l1 + l2} \\ y = \frac{ \frac{2}{3} \times 7 + \frac{1}{3} \times 0 }{ \frac{2}{3} + \frac{1}{3} } \\ y = \frac{14}{3} = 4.7$