PLEASE HELP ME!!!!!!!!!!!!!!!!!
One gallon of paint covers 400 square feet. What is the least amount of paint needed to paint the walls of a room in the shape of a rectangular prism with a length of 20 feet, a width of 16 feet, and a height of 10 feet? Write your answer as a decimal.

Respuesta :

Answer:

1.8 gallons

SEE NOTE BELOW*

Step-by-step explanation:

2x10x16=320

2x20x10=400

400+320=720

720÷400=1.8 gallons

NOTE* This would be painting the four walls.  If you include the floor and ceiling:

2x16x20=640

720+640=1360

1360÷400=3.4 gallons

The least amount of paint needed to paint the walls of a room in the shape of a rectangular prism is 1.8 gallons (2 gallons approx).

What is rectangular prism?

Actually, prisms get their name from the way their faces are shaped. Therefore, a rectangular prism is just a prism with rectangular faces. Although it is a closed, three-dimensional object, two rectangles serve as its foundation.

The formula to calculate the total surface area of a rectangular prism is given as,

TSA of rectangular prism = 2(lb + bh + lh)

Where, l is length, b is breadth and h is the height of the rectangular prism.

Calculation for the paint required for rectangular prism:

The area of the sides of prism to be painted is

Area A = 2×(length×height) + 2×(breadth×height)

Length = 20 feet

Breadth = 16 feet

Height = 10 feet

A = 2×(20×10) + 2×(16×10)

A = 720 sq. feet

Now, the paint need for painting 400 sq. feet is 1 gallon.

Thus, paint required for 720 sq. feet is,

=> 720 ft² / 400 ft² /gal = 1.8 gal  

Therefore, for painting rectangular prism, the amount of paint required is 1.8 gal.

To know more about the prism, here

https://brainly.com/question/16803016

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