Question

solve for x 0°<x<360
3cos2x +sinx=1​

Answer 1

Step-by-step explanation:

3cos2x +sinx=1

3(1-2sin²x)+sinx=1

3-6sin²x+sinx=1

sinx(-6sinx+1)=1

either

sinx=1

sinx=sin(90)

:.x=90

or

-6sinx+1=1

-6sinx=1-1

sinx=0/-6

sinx=sin0,sin180

:.x=0,180and90