I'd like some help in these two questions please, thankyou so much. have a great day! stay safe and stay happy. (there are two parts of one question so uh yea.

Id like some help in these two questions please thankyou so much have a great day stay safe and stay happy there are two parts of one question so uh yea class=

Respuesta :

Answer:

The resultant force is 25 N in the negative x-direction.

Explanation:

We need to find the total force in the x and y-direction and then the resultant force will be the magnitude of the sum of Fx and Fy.

Total force in the x-direction:

[tex]F_{x}=12-37=-25\: N[/tex]

Total force in the y-direction:

[tex]F_{y}=10-10=0\: N[/tex]

Therefore, the magnitude of the resultant force will be:

[tex]F_{R}=\sqrt{F_{x}^{2}+F_{y}^{2}}[/tex]

[tex]F_{R}=\sqrt{(-25)^{2}+0}[/tex]

[tex]|F_{R}|=25\: N[/tex]

The resultant force is 25 N in the negative x-direction, in other words, the car will move to the left.

I hope it helps you!