Question

plz solve it and help me for it​

Answer 1

Given:

Base angle of an isosceles triangle is 15 degrees more than its vertical angle.

To find:

The measure of each angle of the triangle.

Solution:

Let x be the vertical angle. Then,

One base angle = x+15 degrees

We know that base angles of an isosceles triangle are equal.

Another base angle = x+15 degrees

Now, the sum of all angles of a triangle is 180 degrees by the angle sum property.

$x^\circ+(x+15)^\circ+(x+15)^\circ=180^\circ$          (Angle sum property)

$(3x+30)^\circ=180^\circ$

$3x+30=180$

$3x=180-30$

$3x=150$

Divide both sides by 3.

$x=\dfrac{150}{3}$

$x=50$

The measure of base angles is

$(x+15)^\circ=(50+15)^\circ$

$(x+15)^\circ=65^\circ$

Therefore, the measure of angles are 50°, 65° and 65°.