Question

find a and b if
$\sqrt{5} + \sqrt{3} \div \sqrt{5 } - \sqrt{3}$
if a-b√15 ​

Answer 1

Answer:

a=-19/7, b=5/7

Step-by-step explanation:

Answer 2

Answer:

        a = 4     b = -1

Step-by-step explanation:

I think you meant $(\sqrt5+\sqrt3)\div(\sqrt5-\sqrt3)$

Then:

        $(\sqrt5+\sqrt3)\div(\sqrt5-\sqrt3)=\dfrac{\sqrt5+\sqrt3}{\sqrt5-\sqrt3}\cdot\dfrac{\sqrt5+\sqrt3}{\sqrt5+\sqrt3}=\\\\\\=\dfrac{(\sqrt5)^2+2\cdot\sqrt5\cdot\sqrt3+(\sqrt3)^2}{(\sqrt5)^2-(\sqrt3)^2}=\dfrac{5+2\sqrt{15}+3}{5-3}=\dfrac{8+2\sqrt{15}}{2}=\\\\\\=\dfrac{2(4+\sqrt{15})}{2}=4+\sqrt{15}\\\\\\a=4\,,\qquad b=-1$