m/s
3. A ferryboat accelerates from rest at a rate of 0.500 m/s2.
a. What is the velocity of the boat after it has traveled 4.75 m?
b. What is the velocity if the boat has traveled 50 m?

Respuesta :

Lanuel

Answer:

a. Final velocity, V = 2.179 m/s.  

b. Final velocity, V = 7.071 m/s.

Explanation:

Given the following data;

Acceleration = 0.500m/s²

a. To find the velocity of the boat after it has traveled 4.75 m

Since it started from rest, initial velocity is equal to 0m/s.

Now, we would use the third equation of motion to find the final velocity.

[tex] V^{2} = U^{2} + 2aS [/tex]

Where;

  • V represents the final velocity measured in meter per seconds.
  • U represents the initial velocity measured in meter per seconds.
  • a represents acceleration measured in meters per seconds square.
  • S represents the displacement measured in meters.

Substituting into the equation, we have;

[tex] V^{2} = 0^{2} + 2*0.500*4.75 [/tex]

[tex] V^{2} = 4.75 [/tex]

Taking the square root, we have;

[tex] V^{2} = \sqrt {4.75}[/tex]

Final velocity, V = 2.179 m/s.

b. To find the velocity if the boat has traveled 50 m.

[tex] V^{2} = 0^{2} + 2*0.500*50 [/tex]

[tex] V^{2} = 50 [/tex]

Taking the square root, we have;

[tex] V^{2} = \sqrt {50}[/tex]

Final velocity, V = 7.071 m/s.

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