Question

m
A 3.0 kg model train going right at 2.8 bumps into another 2.0 kg model train car moving in the same
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m
direction at 1.6 . The heavier train car has a final speed of 2.2 to the right.
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S
What is the final speed of the lighter 2.0 kg train car?

Answer 1

Answer:

it’s 2.5 m/s

Explanation:

i’m too lazy but trust

Answer 2

This question can be solved by using the law of conservation of momentum.

The final speed of the lighter 2 kg train is " 2.5 ".

When two moving objects collide with each other, the law of conservation of momentum can be applied to them as follows:

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

where,

m₁ = mass of heavier train = 3 kg

m₂ = mass of lighter train = 2 kg

u₁ = initial speed of heavier train = 2.8

u₂ = initial speed of lighter train = 1.6

v₁ = final speed of heavier train = 2.2

v₂ = final speed of lighter train = ?

Therefore,

(3 kg)(2.8) + (2 kg)(1.6) = (3 kg)(2.2) + (2 kg)(v₂)

$v_2 = \frac{5 kg}{2 kg}$

v₂ = 2.5

Learn more about the law of conservation of momentum here:

https://brainly.com/question/1113396?referrer=searchResults

The attached picture illustrates the law of conservation of momentum.