Step-by-step explanation:
First thing you need to do is Slope - intercept form of the line going through point A and B.
Slope-intercept form: y = mx + b (m = slope, b = y-intercept)
To get slope: [tex]\frac{y2 - y1}{x2-x1}[/tex]
Lets set point A as point1 (x1, y1) and point B as point2(x2, y2).
x1 = -4
x2 = 8
y1 = 6
y2 = 3
If you plug these numbers in the slope equations:
[tex]\frac{3 - 6}{8 - 4}[/tex] = [tex]\frac{-3}{4}[/tex]
m = [tex]\frac{-3}{4}[/tex]
So a parallel line is a line that has a different b value but the same slope value.
To get b for the parallel line : we need to substitute the x and y for a given point (0,-2).
which will make -2 = 0([tex]\frac{-3}{4}[/tex] ) + b
now we solve for b:
-2 = 0 +b
b = -2
So the whole Slope-intercept form of the parallel line is: y = [tex]\frac{-3}{4}[/tex] x -2
