Find an equation of the line that contains the point (4,-3) and is perpendicular to the line 2x-3y=4

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Answer:

Step-by-step explanation:

-3y = -2x + 4

3y = 2x - 4

y = 2/3x - 4/3

perp; -3/2

y + 3 = -3/2(x - 4)

y + 3 = -3/2x + 6

y = -3/2x + 3

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