The straight line, Line L has an equation of 4x+y=7. Find the equation of the straight line perpendicular to Line L that passes through (-8,3)

Respuesta :

Answer:

Step-by-step explanation:

y = -4x + 7

perp. 1/4

y - 3 = 1/4(x + 8)

y - 3 = 1/4x + 2

y = 1/4x + 5

The equation of the perpendicular line is y = 1/4x + 5

How to determine the line equation?

The equation is given as:

4x + y = 7

Make y the subject

y = -4x + 7

A linear equation is represented as:

y = mx + c

Where m represents the slope.

This means that:

m = -4

A line perpendicular to 4x + y = 7 will have a slope of:

Slope = -1/m

This gives

Slope = 1/4

The equation of the line is then calculated as:

y = Slope(x - x1) + y1

This gives

y = 1/4(x + 8) + 3

Expand

y = 1/4x + 2 + 3

Evaluate

y = 1/4x + 5

Hence, the equation of the perpendicular line is y = 1/4x + 5

Read more about linear equation at:

https://brainly.com/question/1884491

#SPJ6

ACCESS MORE