Question

The value of (1-w) (1-w*2) , where w is the cube root of the complex number is?

Answer 1

Answer:

3

Step-by-step explanation:

1+ω+w²=0

ω³=1

(1-ω)(1-ω²)=1-ω²-ω+ω³

=1-ω-ω²+1

=2+1-1-ω-ω²

=3-(1+ω+ω²)

=3-0

=3