Question

A student increases the temperature of a 200 cm balloon from 60°C to 120°C.
What will the new volume of the balloon be?
A)100cm^3
B)200cm^3
C)263cm^3
D)400cm^3

Answer 1

Answer:

236 cubic cm

Explanation:

We are given that

Initial volume, V1=200 cubic centimeter

Initial temperature, T1=60 degree Celsius=60+273=333 K

Final temperature, T2=120 degree Celsius=120+273=393 K

Kelvin temperature=Celsius temperature+273

We have to find the new volume of the balloon.

We know that

Charles's law

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Using the formula

$\frac{200}{333}=\frac{V_2}{393}$

$V_2=\frac{200\times 393}{333}$

$V_2=236cm^3$

Hence, the new volume of the balloon will be 236 cubic cm.