Answer:
The equation [tex]x=\frac{-3\pm \sqrt{(3)^2-4(5)(-4)}}{2(5)}[/tex] shows the quadratic formula used correctly to solve the given quadratic equation.
Step-by-step explanation:
The given equation is
[tex]5x^2+3x-4=0[/tex] .... (1)
If a quadratic equation is defined as
[tex]ax^2+bx+c=0[/tex] ..... (2)
then the quadratic formula is
[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
From equation (1) and (2), we get
[tex]a=5,b=3,c=-4[/tex]
Using quadratic formula we get
[tex]x=\frac{-3\pm \sqrt{(3)^2-4(5)(-4)}}{2(5)}[/tex]
Therefore the equation [tex]x=\frac{-3\pm \sqrt{(3)^2-4(5)(-4)}}{2(5)}[/tex] shows the quadratic formula used correctly to solve the given quadratic equation.