Question

a) solve 4(y-7) = 13



b) make t the subject of the formula P =4t - 3

Answer 1

$a)\\ \\4(y-7) = 13\\ \\4y-28=13\\ \\4y=13+28\\ \\4y=41/:4\\ \\y=\frac{41}{4}=10\frac{1}{4}$


$b)\\\\P =4t - 3\\ \\4t=P+3/:4\\ \\t=\frac{P+3}{4}$