álgebra II. Help please...
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Answer:
See below
Step-by-step explanation:
The domain of [tex]f[/tex] is non-negative real numbers, and the domain of [tex]g[/tex] is real numbers.
[tex](f\circ g)(x) = 2\sqrt{2}|x|^5[/tex] (I skipped calculation details), so [tex](f\circ g)(9) = 2 \sqrt{2} \cdot 9^5[/tex].