Solve the equation for x:
sin^2 x – 2 cos x - 2 = 0
for the restriction 0 < x < 2pi
![Solve the equation for x sin2 x 2 cos x 2 0 for the restriction 0 lt x lt 2pi class=](https://us-static.z-dn.net/files/d39/5243540b7ec149768424e015eb7d609f.png)
Answer: x = pi
sin²x - 2cos x - 2 = 0
⇔ 1 - cos²x - 2cos x - 2 = 0
⇔ cos²x + 2cos x + 1 = 0
⇔ (cos x + 1)² = 0
⇒ cos x + 1 = 0
⇔ cos x = -1
⇒ x = pi + k2pi
because 0 ≤ x < 2pi
=> x = pi
Step-by-step explanation: