Can anyone help me?
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Given:
A right angle triangle ABC, right angled at C.
To find:
The measure of θ.
Solution:
In a right angle triangle,
[tex]\tan \theta=\dfrac{Opposite}{Adjacent}[/tex]
In triangle ABC,
[tex]\tan \theta=\dfrac{AC}{BC}[/tex]
[tex]\tan \theta=\dfrac{2.7}{5}[/tex]
[tex]\tan \theta=0.54[/tex]
It can be written as
[tex]\theta=\tan^{-1}0.54[/tex]
[tex]\theta\approx 28.369[/tex]
Therefore, the measure of θ is 28.369.