Question

Im having trouble understanding what the (-) after the x applies to. does it make everything in the () negative therefore i will distribute by (6*-x) and (6*-2)?
6-(x+2)≥4-9x

Answer 1

Answer:

$x \ge 0$

Step-by-step explanation:

Given

$6-(x+2) \ge 4-9x$

Required

Solve

$6-(x+2) \ge 4-9x$

When you distribute -(x+2), the expression becomes:

$6-x-2 \ge 4-9x$

Collect Like Terms

$9x-x \ge 4-6+2$

$8x \ge 0$

Divide both sides by 8

$x \ge \frac{0}{8}$

$x \ge 0$