What is the equation of the line perpendicular to 3x+y=6 that passes through the
point (-6, -1)?
![What is the equation of the line perpendicular to 3xy6 that passes through the point 6 1 class=](https://us-static.z-dn.net/files/d27/eff27bfb09b0a73344de1cae36341ca6.png)
Answer: y = -1/3x - 3
Step-by-step explanation:
First, convert this equation into slope intercept form (y = mx + b where m is the slope and b is the y-intercept)
Next, you need to find the slope of your new equation. The slope of a perpendicular line will have a slope that is the opposite reciprocal of the first slope, which means it will have the opposite sign and the fraction will be flipped (even whole numbers are a fraction - they are divided by 1)
Now that you have your slop, you need to find your y-intercept. To do this, you use the point that you are given. In the previous step, you figured out the slope, so now you can enter that into your new equation. Then, plug the x-coordinate in for x and the y-coordinate in for y in the equation.
The next step is to solve the equation like you would any other equation.
Lastly, create your new equation in slope-intercept form with the values you have found.