Question

PLEASE HELP!! WILL MARK BRAINLIEST! THANK YOUUUU
An equilateral triangle has a side length of 40.

Another side of the same triangle measures 3x​ + y.
The third side of the same triangle measures 4x​ - 2y.
What are the values of x and y that would keep the triangle​ equilateral?

Answer 1

Answer:

x=12

y = 4

Step-by-step explanation:

3x + y = 4x - 2y

x = 3y

y= 1/3x

3x + y = 40             3x + y = 40

3(3y) + y = 40         3x + (1/3x) = 40

9y + y =40              10/3x = 40

10y = 40                  x = 12

y= 4

Answer 2

Answer:

We know that all sides of the equilateral triangle is equal.

Given :---

An equilateral triangle has a side length of 40.

Another side of the same triangle measures

3x + y.

The third side of the same triangle measures

4x - 2y.

According to the above problem, the equation are

3x+y=40........(i) and 4x-2y=40.........(ii)

Divide the equation (ii) by 2, we get

2x-y=20..........(iii)

Now solving for x and y we get,

3x+y=40.......(i)

2x-y=20........(iii)

5x =60

x=60/5

x=12

Putting the value of x in equation in equation (iii) we get

24-y=20

y=24-20

y=4

The values of x and y that would keep the triangle equilateral are 12 and 4 respectively.

Hence, the value of x is 12 and y is 4.