A 3.6-kg chihuahua charges at a speed of 3.3m/s. what is the magnitude of the average force needed to bring the chihuahua to a stop in 0.50s?

Respuesta :

... 
use this equation 
F delta(t) = m delta(v) 
F (0.50) = 3.6 (3.3) 
F = 23.8 N 
ACCESS MORE