Question

my question is in the attachment

Answer 1

Answer:

x = 1

Step-by-step explanation:

$\frac{4x-1}{2}+\frac{3x+4}{3}= \frac{23}{6}$

$\frac{3(4x-1)}{6}+\frac{2(3x+4)}{6}= \frac{23}{6}$

$\frac{12x-3+6x+8}{6}=\frac{23}{6}$

18x + 5 = 23

18x = 23 - 5

18x = 18

x = 1

Therefore, x = 1 is the solution of the given expression.