a A student decreases the temperature of a 484 cm ^ 3 balloon from 570 K to 285 Assuming constant pressure, what should the new volume of the balloon be? Round your answer to one decimal place.
![a A student decreases the temperature of a 484 cm 3 balloon from 570 K to 285 Assuming constant pressure what should the new volume of the balloon be Round your class=](https://us-static.z-dn.net/files/d1e/21f1ff3007301e273fa8a01d6c8465e8.png)
Answer:
242 cm³.
Explanation:
The following data were obtained from the question:
Initial volume (V₁) = 484 cm³
Initial temperature (T₁) = 570 K
Final temperature (T₂) = 285 K
Pressure = constant
Final volume (V₂) =?
The new volume (i.e final volume) of the balloon can be obtained by using the Charles' law equation as illustrated below:
V₁/T₁ = V₂/T₂
484 / 570 = V₂ / 285
Cross
484 × 285 = 570 × V₂
137940 = 570 × V₂
Divide both side by 570
V₂ = 137940 / 570
V₂ = 242 cm³
Therefore, the new volume of the balloon is 242 cm³