01-02-2021
Chemistry

contestada

How many molecules are in 643.21 grams of Mg3(PO4)2?

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gizelleramirez05 gizelleramirez05

02-02-2021

Answer:

643.21g 1 mol 6.022^23

262.87 g 1 mol

= 1.4735E24 [Mg3(PO4)2]

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