Can someone explain the process of getting to Angle A? I know the answer is 44.1 but I need to show my work so can someone show me the process of getting the answer and please explain! Thank you!!
![Can someone explain the process of getting to Angle A I know the answer is 441 but I need to show my work so can someone show me the process of getting the answ class=](https://us-static.z-dn.net/files/dbb/f8bb4bd3b125cbb993e387f10c2295a6.png)
Answer:
Step-by-step explanation:
First you have to calculate CB in order to use sin law to calculate ∠A
CB=[tex]\sqrt{18.4^{2} -13.2^{2} }[/tex]
CB=12.8(correct to nearest tenth)
After that, use sin law to calculate ∠A,
[tex]\frac{18.4}{sin90} =\frac{12.8}{sinA}[/tex] or [tex]\frac{sin90}{18.4} =\frac{sinA}{12.8}[/tex]
sinA=0.695...
A=44.079...
=44.1(corrext to the nearest tenth)
Is that clear enough for you?